Two resistors of 4 Ω each are joined in series. Their total resistance is A2 Ω B4 Ω C8 Ω D16 Ω Tap an answer to check. Show the answer Answer: C. 8 Ω In series, resistances add: 4 + 4 = 8 Ω. Report a problem The answer is wrong Spelling or typing mistake The question is unclear Out of date Something else Send